Friday, March 23, 2007

Omaha/8 question

While playing at Harrah's Council Bluffs I ran into an interesting situation. I wasn't even in the hand so none of this cost me any money, but I still can't figure out what the hell was going on. We were playing 4/8 Omaha H/L and on one of the hands the flop was 876 (the two other cards were higher than 8). When the hand ended two players were playing for the low. One of them had 32 and one had A5.

Who wins the low and why?

UPDATE: So I guess I am the only donkey who doesn't know that a 32 low is better than a A5 low. I understand the reasoning now, but actually have a simple way to remember this moving forward. 32 < 51 (where A=1). That makes it a whole lot easier to remember. Almost as easy as 5xSB.

Thanks to Bayne and Hoyazo for their comments!

2 comments:

bayne_s said...

876 32 is lower than 876 5A.

For purposes of a low Ace is smaller than 2 but otherwise you look at it as whose high hand is worse.

Both have an 8 high

Hammer Player a.k.a Hoyazo said...

Yeah I'm not sure what the confusion here is, but the way low hands are valued in all forms of low poker is you start with the highest hand in the 5-card low hand, and move your way backwards until one card is lower than the corresponding card in the other hand.

In this case as Bayne says it is 87632 against 8765A. So you start with the highest card in each hand -- in this case it is 8 vs 8. Since neither is higher or lower than the other, we move on to the next card -- 7 vs 7. So we move to the next card -- 6 vs 6. With another tie, we move on to the next card, which is a 3 vs. a 5. Here since these corresponding cards are different, the lower card wins the hand. As Bayne says, 87632 is lower than 8765A, because an 8763 low is lower than an 8765 low, and the 8765 low is among the roughest (highest) possible low hands one can have.